배움 저장소
[Leet Code] 006 ZigZag Conversion 본문
class Solution {
public:
string convert(string s, int numRows) {
if(numRows==1) return s;
int divider = numRows + numRows-2;
vector<string> matrix(numRows);
for(int i=0; i<s.size(); ++i){
int index = i % divider;
if(index < numRows)
{
matrix.at(index%numRows).push_back(s[i]);
}
else
{
index = index % (numRows-1);
matrix.at(numRows-1-index).push_back(s[i]);
}
}
string result;
for(string str:matrix){
result.append(str);
for(char c:str){
cout << c << " ";
}
cout << endl;
}
return result;
}
};
'PS > LeetCode' 카테고리의 다른 글
[Leet Code]055 Jump Game (0) | 2021.10.06 |
---|---|
[Leet Code]009 Palindorme Number (0) | 2021.05.21 |
[Leet Code]007 Reverse Integer (0) | 2021.05.12 |
[LeetCode] 002 Add Two Numbers (0) | 2021.04.20 |
[LeetCode] 001 Two Sum (0) | 2021.04.20 |
Comments